15t^2-150t+240=0

Solution for 15t^2-150t+240=0 equation:

15t^2-150t+240=0

a = 15; b = -150; c = +240;
Δ = b2-4ac
Δ = -1502-4·15·240
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-90}{2*15}=\frac{60}{30}
=2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+90}{2*15}=\frac{240}{30}
=8
$